About momentum with Minute Physics

Normally, we know that momentum is p=mv, but the real equation is p= mv/ √(1-v^2/c^2). At low speed the equation will become p=mv, but at close enough speed it will be usable in it’s more complex form.

Judging by the formula we can understand why it is hard to obtain speed greater than the speed of light. If you will want to obtain a speed as high as 2c then the result of that equation would be p=2mc/√-3. Ooops.

The energy would be:

Momentul at speed=2c would be:

Use that in the energy equation from above and you get:

If you go further and calculate for 1kg of mass then you get 7/3c^2 or 18.0 × 10^16 joules per kilogram or about twice as the 21 kt of TNT nuclear bomb that was thrown over Nagasaki. Hmm, would it be then possible to accelerate a 1kg object to twice the speed of light with that much energy? I guess I’m missing some insight. Care to weigh in?

PS. I use mathurl to obtain those neat math images.

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